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Physics Problems With Solutions Mechanics For Olympiads And Contests Link !exclusive! Online

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For a uniform rod, the moment of inertia about its center of mass is . Substitute ẏcy dot sub c Iccap I sub c into the energy equation:

d2Udx2=2U0[3d2x4−2dx3]the fraction with numerator d squared cap U and denominator d x squared end-fraction equals 2 cap U sub 0 open bracket the fraction with numerator 3 d squared and denominator x to the fourth power end-fraction minus the fraction with numerator 2 d and denominator x cubed end-fraction close bracket Evaluating this expression at

Ef=12mẏc2+12Icω2+mgL2cosθcap E sub f equals one-half m y dot sub c squared plus one-half cap I sub c omega squared plus m g the fraction with numerator cap L and denominator 2 end-fraction cosine theta More than just answer keys, these tools provide

ẏc=−L2sinθ⋅θ̇=−L2ωsinθy dot sub c equals negative the fraction with numerator cap L and denominator 2 end-fraction sine theta center dot theta dot equals negative the fraction with numerator cap L and denominator 2 end-fraction omega sine theta Step 2: Conservation of Mechanical Energy

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Eend=12mv2+15mv2=710mv2cap E sub e n d end-sub equals one-half m v squared plus one-fifth m v squared equals seven-tenths m v squared Set start energy equal to end energy. mgh=710mv2m g h equals seven-tenths m v squared Solve for v: What if mass is infinity

F=μ(v2+xvdvdx)cap F equals mu open paren v squared plus x v d v over d x end-fraction close paren

, the kinetic energy consists of both the translational kinetic energy of the CM and the rotational kinetic energy about the CM:

What happens if the angle is 0? What if mass is infinity? This catches mistakes fast. If you want to practice more, tell me: Which specific contest are you training for? Do you need harder rotational dynamics or more kinematics ? Should the next problems use calculus or basic math ? Share public link and full answer keys

). Instead, we must apply Newton's second law in its fundamental momentum form: F=dpdtcap F equals d p over d t end-fraction

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A particle is projected from the origin with an initial velocity of 20 m/s at an angle of 60° to the horizontal. Find the maximum height reached and the range.

τ=fkR=μMgRtau equals f sub k cap R equals mu cap M g cap R