9.1.7 Checkerboard V2 Codehs Jun 2026

In Version 1, you might have filled entire rows. In V2, you must alternate within the row. Pro-Tip for Advanced Users

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In , you might have created a static 8x8 board. In Checkerboard V2 , the requirements typically change in one of two ways (depending on your school’s version):

Have questions or an alternate solution? Drop a comment below! 9.1.7 Checkerboard V2 Codehs

def print_board(board): for i in range(len(board)): print(" ".join([str(x) for x in board[i]]))

In CodeHS, this problem is typically solved in Java using standard nested loops. Below is the structured approach to implementing this logic cleanly.

Do you need help understanding the math? Share public link In Version 1, you might have filled entire rows

The key takeaway is the sum of the indices: Step-by-Step Implementation Guide

Master this, and you have unlocked a fundamental pattern used in game development, graphics programming, and algorithm design.

: You must use a loop inside another loop—typically an outer loop for the rows and an inner loop for the columns—to traverse every coordinate in the grid. This link or copies made by others cannot be deleted

Use the (row + col) % 2 formula. Never hardcode each tile.

What does the grid store? (Integers, Strings, Colors?) Share public link

A clean solution relies on nested loops: an outer loop to control the rows and an inner loop to control the individual columns within those rows.

You need two loops: an outer loop for rows and an inner loop for columns.